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Oracle 1z0-071 exam, also known as the Oracle Database SQL exam, is a certification exam designed to evaluate the skills and knowledge of individuals in SQL database management. 1z0-071 Exam is intended for database administrators, developers, and IT professionals who use SQL as a part of their daily work. 1z0-071 exam is divided into multiple sections that cover different aspects of SQL, such as data retrieval, manipulation, and management. 1z0-071 exam validates the ability to use SQL to manage data in an Oracle database environment, as well as the ability to create and maintain database objects such as tables, views, and indexes.
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Oracle 1z0-071, also known as the Oracle Database SQL certification exam, is a widely recognized and respected certification for professionals working with databases. 1z0-071 exam tests the individual's knowledge and understanding of the SQL language and its use in managing and manipulating data within an Oracle database environment. Passing 1z0-071 Exam is a valuable asset to professionals who work with Oracle databases, and it proves their expertise and proficiency in the SQL language.
Oracle Database SQL Sample Questions (Q51-Q56):
NEW QUESTION # 51
Which two statements are true about * _TABLES views?
- A. USER TABLES displays all tables owned by the current user.
- B. You must have ANY TABLE system privileges, or be granted object privileges on the table, to view a table in USER_TABLES.
- C. ALL TABLES displays all tables owned by the current user.
- D. You must have ANY TABLE system privileges, or be granted object privilges on the table, to viewa tabl e in DBA TABLES.
- E. You must have ANY TABLE system privileges, or be granted object privileges on the table, to view a table in ALL_TABLES.
- F. All users can query DBA_TABLES successfully.
Answer: A,D
NEW QUESTION # 52
The sales table has columns prod_id and quantity_sold of data type number. Which two queries execute successfully?
- A. SELECT prod_id FROM sales WHERE quantity_sold > 55000 AND COUNT(*) > 10 GROUP BY prod_id HAVING COUNT(*) > 10;
- B. SELECT COUNT(prod_id) FROM sales WHERE quantity_sold > 55000 GROUP BY prod_id;
- C. SELECT prod_id FROM sales WHERE quantity_sold > 55000 AND
COUNT(*) > 10 GROUP BY COUNT(*) > 10; - D. SELECT prod Id FROH sales NHERE quantity sold > 55000 3RODI BY prod_id HAVING COUNT(*)
> 10; - E. SELECT COUNT(prod_id) FROM sales GROUP BY prod_id WHERE quantity_sold > 55000;
Answer: B,D
NEW QUESTION # 53
Examine the structure of the ORDERS table:
You want to find the total value of all the orders for each year and issue this command:
SQL> SELECT TO_CHAR(order_date,'rr'), SUM(order_total) FROM orders
GROUP BY TO_CHAR(order_date, 'yyyy');
Which statement is true regarding the result? (Choose the best answer.)
- A. It executes successfully but does not give the correct output.
- B. It executes successfully and gives the correct output.
- C. It return an error because the datatype conversion in the SELECT list does not match the data type conversion in the GROUP BY clause.
- D. It returns an error because the TO_CHAR function is not valid.
Answer: C
NEW QUESTION # 54
Examine this partial statement:
SELECT ename, sal,comm FROM emp
Now examine this output:
WHICH ORDER BY clause will generate the displayed output?
- A. ORDER BY NVL(comm,0) ASC NULLS FIRST, ename
- B. ORDER BY NVL(comm,0) ASC NULLS LAST, ename
- C. ORDER BY comm DESC NULLS LAST, ename
- D. ORDER BY NVL(enam,0) DESC, ename
Answer: A
Explanation:
The ORDER BY clause is used in a SELECT statement to sort the returned rows by one or more columns.
A). This clause would attempt to order by ename as if it were a numeric column, which is not correct since ename is not numeric.
B). This is the correct answer. The NVL function replaces nulls with the specified value, in this case, 0. This clause sorts by comm, with nulls considered as 0 and appearing first, followed by the actual values, and then sorts by ename.
C). This clause is incorrect because it would place null values at the end, but in the output, rows with null comm appear at the beginning.
D). This clause would sort the comm in descending order with the nulls at the end, which is not consistent with the output shown.
References:
* Oracle Database SQL Language Reference, 12c Release 1 (12.1): "ORDER BY Clause"
* Oracle Database SQL Language Reference, 12c Release 1 (12.1): "NVL Function" Please note that the correct formatting of SQL statements and clauses is crucial for the successful execution of queries.
NEW QUESTION # 55
Which two are true about external tables that use the ORACLE _DATAPUMP access driver?
- A. When creating an external table, data can be selected only from a table whose rows are stored in database blocks.
- B. Creating an external table creates a dump file that can be used only by an external table in the same database.
- C. Creating an external table creates a dump file that can be used by an external table in the same or a different database.
- D. Creating an external table creates a directory object.
- E. When creating an external table, data can be selected from another external table or from a table whose rows are stored in database blocks.
Answer: E
Explanation:
External tables using the ORACLE_DATAPUMP access driver have specific characteristics:
C). Creating an external table using the ORACLE_DATAPUMP access driver allows you to select data from other tables, including another external table or a regular table whose rows are stored in database blocks.
A, B, D, and E are incorrect. Specifically:
* A is incorrect because creating an external table does not automatically create a directory object; the
* directory object must exist prior to or be created separately.
* B is incorrect as it limits the creation to tables stored in database blocks, which is not a restriction.
* D is incorrect because creating an external table does not create a dump file; it reads from an existing dump file created by Data Pump.
* E is also incorrect because the dump file is not created as part of the external table creation process.
References:
* Oracle Database SQL Language Reference, 12c Release 1 (12.1): "CREATE TABLE" for External Tables
NEW QUESTION # 56
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